131324117 has 2 divisors, whose sum is σ = 131324118. Its totient is φ = 131324116.

The previous prime is 131324111. The next prime is 131324183. The reversal of 131324117 is 711423131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119552356 + 11771761 = 10934^2 + 3431^2 .

It is an emirp because it is prime and its reverse (711423131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131324117 - 2⁴ = 131324101 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131324092 and 131324101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131324111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662058 + 65662059.

It is an arithmetic number, because the mean of its divisors is an integer number (65662059).

Almost surely, 2^131324117 is an apocalyptic number.

It is an amenable number.

131324117 is a deficient number, since it is larger than the sum of its proper divisors (1).

131324117 is an equidigital number, since it uses as much as digits as its factorization.

131324117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 504, while the sum is 23.

The square root of 131324117 is about 11459.6735119287. The cubic root of 131324117 is about 508.2938204051.

Adding to 131324117 its reverse (711423131), we get a palindrome (842747248).

The spelling of 131324117 in words is "one hundred thirty-one million, three hundred twenty-four thousand, one hundred seventeen".