Base | Representation |
---|---|
bin | 11101110111001000000001… |
… | …010001001000010111110101 |
3 | 122020000011122012221221200112 |
4 | 131313020001101020113311 |
5 | 114203213433444320140 |
6 | 1143152512245352405 |
7 | 36443250526432235 |
oct | 3567100121102765 |
9 | 566004565857615 |
10 | 131331531245045 |
11 | 3893443164451a |
12 | 12890b20108705 |
13 | 5838683056571 |
14 | 24606a12a9cc5 |
15 | 102b37b764c65 |
hex | 7772014485f5 |
131331531245045 has 64 divisors (see below), whose sum is σ = 171619650429696. Its totient is φ = 96115291852800.
The previous prime is 131331531244889. The next prime is 131331531245051. The reversal of 131331531245045 is 540542135133131.
It is not a de Polignac number, because 131331531245045 - 222 = 131331527050741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131331531244993 and 131331531245011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 168142502 + ... + 168921768.
It is an arithmetic number, because the mean of its divisors is an integer number (2681557037964).
Almost surely, 2131331531245045 is an apocalyptic number.
It is an amenable number.
131331531245045 is a deficient number, since it is larger than the sum of its proper divisors (40288119184651).
131331531245045 is a wasteful number, since it uses less digits than its factorization.
131331531245045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779750.
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 131331531245045 its reverse (540542135133131), we get a palindrome (671873666378176).
The spelling of 131331531245045 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, five hundred thirty-one million, two hundred forty-five thousand, forty-five".
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