1313435602040 has 64 divisors (see below), whose sum is σ = 2959541323200. Its totient is φ = 524608293888.

The previous prime is 1313435602019. The next prime is 1313435602057. The reversal of 1313435602040 is 402065343131.

It is a super-2 number, since 2×1313435602040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313435601988 and 1313435602006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114835202 + ... + 114846638.

It is an arithmetic number, because the mean of its divisors is an integer number (46242833175).

Almost surely, 2^{1313435602040} is an apocalyptic number.

1313435602040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313435602040 is an abundant number, since it is smaller than the sum of its proper divisors (1646105721160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313435602040 is a wasteful number, since it uses less digits than its factorization.

1313435602040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15384 (or 15380 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 32.

The spelling of 1313435602040 in words is "one trillion, three hundred thirteen billion, four hundred thirty-five million, six hundred two thousand, forty".