Base | Representation |
---|---|
bin | 11101110111011001100010… |
… | …011100101110111000110000 |
3 | 122020001222012010212012222220 |
4 | 131313121202130232320300 |
5 | 114204020444413424040 |
6 | 1143205302555401040 |
7 | 36444514624361346 |
oct | 3567314234567060 |
9 | 566058163765886 |
10 | 131350341545520 |
11 | 38941404562699 |
12 | 128946ab753180 |
13 | 583a390105286 |
14 | 2461567583996 |
15 | 102baccd2c2d0 |
hex | 77766272ee30 |
131350341545520 has 160 divisors (see below), whose sum is σ = 419985905556672. Its totient is φ = 33933821607936.
The previous prime is 131350341545513. The next prime is 131350341545531. The reversal of 131350341545520 is 25545143053131.
It is a super-3 number, since 3×1313503415455203 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29672817 + ... + 33810896.
Almost surely, 2131350341545520 is an apocalyptic number.
131350341545520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131350341545520 is an abundant number, since it is smaller than the sum of its proper divisors (288635564011152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131350341545520 is a wasteful number, since it uses less digits than its factorization.
131350341545520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63483999 (or 63483993 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 131350341545520 its reverse (25545143053131), we get a palindrome (156895484598651).
The spelling of 131350341545520 in words is "one hundred thirty-one trillion, three hundred fifty billion, three hundred forty-one million, five hundred forty-five thousand, five hundred twenty".
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