Base | Representation |
---|---|
bin | 10011000111011011010… |
… | …001100001101011110000 |
3 | 11122120202002121211102012 |
4 | 103013123101201223300 |
5 | 133010320310030000 |
6 | 2443251334142052 |
7 | 163623214214405 |
oct | 23073321415360 |
9 | 4576662554365 |
10 | 1313643830000 |
11 | 467127771657 |
12 | 1927147b1928 |
13 | 96b5099c928 |
14 | 4781b62a2ac |
15 | 24286b51735 |
hex | 131db461af0 |
1313643830000 has 50 divisors (see below), whose sum is σ = 3180463101024. Its totient is φ = 525457528000.
The previous prime is 1313643829957. The next prime is 1313643830011. The reversal of 1313643830000 is 383463131.
It is a tau number, because it is divible by the number of its divisors (50).
It is a super-2 number, since 2×13136438300002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 65672192 + ... + 65692191.
Almost surely, 21313643830000 is an apocalyptic number.
1313643830000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1313643830000 is an abundant number, since it is smaller than the sum of its proper divisors (1866819271024).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313643830000 is an equidigital number, since it uses as much as digits as its factorization.
1313643830000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131364411 (or 131364390 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 1313643830000 in words is "one trillion, three hundred thirteen billion, six hundred forty-three million, eight hundred thirty thousand".
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