Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …0001000001010000001010 |
3 | 1201112012102210201021102211 |
4 | 2333031313201001100022 |
5 | 3210242323341244200 |
6 | 43540324121015334 |
7 | 2524233063656254 |
oct | 277156741012012 |
9 | 51465383637384 |
10 | 13140310103050 |
11 | 4206857538949 |
12 | 158281b32454a |
13 | 744183874930 |
14 | 335dcc8d6cd4 |
15 | 17bc22710aba |
hex | bf37784140a |
13140310103050 has 48 divisors (see below), whose sum is σ = 26321721864480. Its totient is φ = 4851683317440.
The previous prime is 13140310103033. The next prime is 13140310103057. The reversal of 13140310103050 is 5030101304131.
It is not an unprimeable number, because it can be changed into a prime (13140310103057) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27622509 + ... + 28094191.
It is an arithmetic number, because the mean of its divisors is an integer number (548369205510).
Almost surely, 213140310103050 is an apocalyptic number.
13140310103050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140310103050 is an abundant number, since it is smaller than the sum of its proper divisors (13181411761430).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140310103050 is a wasteful number, since it uses less digits than its factorization.
13140310103050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 514567 (or 514562 counting only the distinct ones).
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13140310103050 its reverse (5030101304131), we get a palindrome (18170411407181).
The spelling of 13140310103050 in words is "thirteen trillion, one hundred forty billion, three hundred ten million, one hundred three thousand, fifty".
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