Base | Representation |
---|---|
bin | 1011111100111101110001… |
… | …1011011000100011011000 |
3 | 1201112100210210102200011202 |
4 | 2333033130123120203120 |
5 | 3210304310244440230 |
6 | 43541204120213332 |
7 | 2524323042264551 |
oct | 277173433304330 |
9 | 51470723380152 |
10 | 13142003124440 |
11 | 4207546174983 |
12 | 158301230a248 |
13 | 744393549938 |
14 | 33610d6c3328 |
15 | 17bcc1186a45 |
hex | bf3dc6d88d8 |
13142003124440 has 32 divisors (see below), whose sum is σ = 31308889798080. Its totient is φ = 4947577646592.
The previous prime is 13142003124409. The next prime is 13142003124461. The reversal of 13142003124440 is 4442130024131.
It is a super-2 number, since 2×131420031244402 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9663236912 + ... + 9663238271.
It is an arithmetic number, because the mean of its divisors is an integer number (978402806190).
Almost surely, 213142003124440 is an apocalyptic number.
13142003124440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142003124440 is an abundant number, since it is smaller than the sum of its proper divisors (18166886673640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142003124440 is a wasteful number, since it uses less digits than its factorization.
13142003124440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19326475211 (or 19326475207 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13142003124440 its reverse (4442130024131), we get a palindrome (17584133148571).
The spelling of 13142003124440 in words is "thirteen trillion, one hundred forty-two billion, three million, one hundred twenty-four thousand, four hundred forty".
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