Base | Representation |
---|---|
bin | 11101111000011011101000… |
… | …100101000001011011011100 |
3 | 122020022202101011001102221202 |
4 | 131320123220211001123130 |
5 | 114211201321200423200 |
6 | 1143302041132415032 |
7 | 36452606415606020 |
oct | 3570335045013334 |
9 | 566282334042852 |
10 | 131421311342300 |
11 | 38969513119401 |
12 | 128a63b7317478 |
13 | 5843c90443475 |
14 | 2464b7acc4380 |
15 | 102d8836551d5 |
hex | 7786e89416dc |
131421311342300 has 72 divisors (see below), whose sum is σ = 333504499929216. Its totient is φ = 44010857741760.
The previous prime is 131421311342267. The next prime is 131421311342317. The reversal of 131421311342300 is 3243113124131.
It is a super-2 number, since 2×1314213113423002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2183048162 + ... + 2183108361.
Almost surely, 2131421311342300 is an apocalyptic number.
131421311342300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131421311342300 is an abundant number, since it is smaller than the sum of its proper divisors (202083188586916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131421311342300 is a wasteful number, since it uses less digits than its factorization.
131421311342300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4366156587 (or 4366156580 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 131421311342300 its reverse (3243113124131), we get a palindrome (134664424466431).
The spelling of 131421311342300 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, three hundred eleven million, three hundred forty-two thousand, three hundred".
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