Base | Representation |
---|---|
bin | 1011111100111111010011… |
… | …1010110001010010011000 |
3 | 1201112101212102120120220002 |
4 | 2333033310322301102120 |
5 | 3210311130441133100 |
6 | 43541312554552132 |
7 | 2524336161565331 |
oct | 277176472612230 |
9 | 51471772516802 |
10 | 13142414005400 |
11 | 42077370a1919 |
12 | 1583107a38648 |
13 | 74442a6caa74 |
14 | 33614c0bb288 |
15 | 17bce72992d5 |
hex | bf3f4eb1498 |
13142414005400 has 96 divisors (see below), whose sum is σ = 30617387348400. Its totient is φ = 5246430412800.
The previous prime is 13142414005361. The next prime is 13142414005403. The reversal of 13142414005400 is 450041424131.
It is a super-3 number, since 3×131424140054003 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13142414005403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 340802120 + ... + 340840680.
Almost surely, 213142414005400 is an apocalyptic number.
13142414005400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142414005400 is an abundant number, since it is smaller than the sum of its proper divisors (17474973343000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142414005400 is a wasteful number, since it uses less digits than its factorization.
13142414005400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41949 (or 41940 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 13142414005400 its reverse (450041424131), we get a palindrome (13592455429531).
The spelling of 13142414005400 in words is "thirteen trillion, one hundred forty-two billion, four hundred fourteen million, five thousand, four hundred".
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