Base | Representation |
---|---|
bin | 1011111100111111010101… |
… | …1111001011111001000010 |
3 | 1201112101220002112120202100 |
4 | 2333033311133023321002 |
5 | 3210311140412122204 |
6 | 43541313535331230 |
7 | 2524336335664563 |
oct | 277176537137102 |
9 | 51471802476670 |
10 | 13142423551554 |
11 | 4207741522000 |
12 | 158310b080b16 |
13 | 74442c690b8b |
14 | 33614d48416a |
15 | 17bce8032a39 |
hex | bf3f57cbe42 |
13142423551554 has 48 divisors (see below), whose sum is σ = 31320636800544. Its totient is φ = 3982552584120.
The previous prime is 13142423551553. The next prime is 13142423551591. The reversal of 13142423551554 is 45515532424131.
13142423551554 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 2 + 42 + 3 + 5 + 51 + 554 = 666.
It is not an unprimeable number, because it can be changed into a prime (13142423551553) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 274256524 + ... + 274304439.
It is an arithmetic number, because the mean of its divisors is an integer number (652513266678).
Almost surely, 213142423551554 is an apocalyptic number.
13142423551554 is an abundant number, since it is smaller than the sum of its proper divisors (18178213248990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142423551554 is a wasteful number, since it uses less digits than its factorization.
13142423551554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 548561004 (or 548560979 counting only the distinct ones).
The product of its digits is 1440000, while the sum is 45.
Adding to 13142423551554 its reverse (45515532424131), we get a palindrome (58657955975685).
The spelling of 13142423551554 in words is "thirteen trillion, one hundred forty-two billion, four hundred twenty-three million, five hundred fifty-one thousand, five hundred fifty-four".
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