Base | Representation |
---|---|
bin | 10011001000001010011… |
… | …001001000001110000000 |
3 | 11122122210012010111201210 |
4 | 103020022121020032000 |
5 | 133013430143231000 |
6 | 2443502013530120 |
7 | 163651623434310 |
oct | 23101231101600 |
9 | 4578705114653 |
10 | 1314434352000 |
11 | 4674a2a19520 |
12 | 1928b54a3940 |
13 | 96c486b4723 |
14 | 47894609440 |
15 | 242d1255350 |
hex | 1320a648380 |
1314434352000 has 1024 divisors, whose sum is σ = 5459776358400. Its totient is φ = 271761408000.
The previous prime is 1314434351981. The next prime is 1314434352017. The reversal of 1314434352000 is 2534344131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 846383224 + ... + 846384776.
It is an arithmetic number, because the mean of its divisors is an integer number (5331812850).
Almost surely, 21314434352000 is an apocalyptic number.
1314434352000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1314434352000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2729888179200).
1314434352000 is an abundant number, since it is smaller than the sum of its proper divisors (4145342006400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314434352000 is a wasteful number, since it uses less digits than its factorization.
1314434352000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1832 (or 1810 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 1314434352000 its reverse (2534344131), we get a palindrome (1316968696131).
The spelling of 1314434352000 in words is "one trillion, three hundred fourteen billion, four hundred thirty-four million, three hundred fifty-two thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •