1314861000432 has 120 divisors (see below), whose sum is σ = 4123086926976. Its totient is φ = 359340879744.

The previous prime is 1314861000331. The next prime is 1314861000451. The reversal of 1314861000432 is 2340001684131.

It is a junction number, because it is equal to n+sod(n) for n = 1314861000393 and 1314861000402.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12098938 + ... + 12207129.

Almost surely, 2^{1314861000432} is an apocalyptic number.

1314861000432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1314861000432 is an abundant number, since it is smaller than the sum of its proper divisors (2808225926544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314861000432 is a wasteful number, since it uses less digits than its factorization.

1314861000432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24306115 (or 24306102 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 1314861000432 its reverse (2340001684131), we get a palindrome (3654862684563).

The spelling of 1314861000432 in words is "one trillion, three hundred fourteen billion, eight hundred sixty-one million, four hundred thirty-two", and thus it is an aban number.