1316233611040 has 48 divisors (see below), whose sum is σ = 3113030696832. Its totient is φ = 525912908544.

The previous prime is 1316233611029. The next prime is 1316233611067. The reversal of 1316233611040 is 401163326131.

It is a junction number, because it is equal to n+sod(n) for n = 1316233610993 and 1316233611011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4389864 + ... + 4680103.

It is an arithmetic number, because the mean of its divisors is an integer number (64854806184).

Almost surely, 2^{1316233611040} is an apocalyptic number.

1316233611040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1316233611040 is an abundant number, since it is smaller than the sum of its proper divisors (1796797085792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1316233611040 is an equidigital number, since it uses as much as digits as its factorization.

1316233611040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9070889 (or 9070881 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 1316233611040 its reverse (401163326131), we get a palindrome (1717396937171).

The spelling of 1316233611040 in words is "one trillion, three hundred sixteen billion, two hundred thirty-three million, six hundred eleven thousand, forty".