Base | Representation |
---|---|
bin | 1100000000010111010111… |
… | …0101010010011110101000 |
3 | 1201201221120100220201020111 |
4 | 3000011311311102132220 |
5 | 3212233420304413300 |
6 | 44024104004304104 |
7 | 2531461333415506 |
oct | 300056565223650 |
9 | 51657510821214 |
10 | 13200411404200 |
11 | 422a299115a69 |
12 | 15923b30a2034 |
13 | 749a412ac917 |
14 | 338c909d9676 |
15 | 17d58dcc39ba |
hex | c0175d527a8 |
13200411404200 has 48 divisors (see below), whose sum is σ = 30694257048960. Its totient is φ = 5279596728000.
The previous prime is 13200411404189. The next prime is 13200411404249. The reversal of 13200411404200 is 240411400231.
It is a happy number.
It is a super-2 number, since 2×132004114042002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1682106 + ... + 5406505.
It is an arithmetic number, because the mean of its divisors is an integer number (639463688520).
Almost surely, 213200411404200 is an apocalyptic number.
13200411404200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13200411404200 is an abundant number, since it is smaller than the sum of its proper divisors (17493845644760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200411404200 is a wasteful number, since it uses less digits than its factorization.
13200411404200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7097938 (or 7097929 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 13200411404200 its reverse (240411400231), we get a palindrome (13440822804431).
The spelling of 13200411404200 in words is "thirteen trillion, two hundred billion, four hundred eleven million, four hundred four thousand, two hundred".
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