Base | Representation |
---|---|
bin | 1100000000010111011110… |
… | …0100000001101000110000 |
3 | 1201201221122101112112112122 |
4 | 3000011313210001220300 |
5 | 3212234000222330300 |
6 | 44024110522413412 |
7 | 2531462135231246 |
oct | 300056744015060 |
9 | 51657571475478 |
10 | 13200440433200 |
11 | 422a303542979 |
12 | 1592400961268 |
13 | 749a47304947 |
14 | 338c947d4796 |
15 | 17d591609c85 |
hex | c0177901a30 |
13200440433200 has 120 divisors (see below), whose sum is σ = 33409385568720. Its totient is φ = 4998351283200.
The previous prime is 13200440433127. The next prime is 13200440433259. The reversal of 13200440433200 is 233404400231.
It is a super-2 number, since 2×132004404332002 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13200440433200.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9025130 + ... + 10385270.
It is an arithmetic number, because the mean of its divisors is an integer number (278411546406).
Almost surely, 213200440433200 is an apocalyptic number.
13200440433200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13200440433200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16704692784360).
13200440433200 is an abundant number, since it is smaller than the sum of its proper divisors (20208945135520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200440433200 is a wasteful number, since it uses less digits than its factorization.
13200440433200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1361455 (or 1361444 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 13200440433200 its reverse (233404400231), we get a palindrome (13433844833431).
The spelling of 13200440433200 in words is "thirteen trillion, two hundred billion, four hundred forty million, four hundred thirty-three thousand, two hundred".
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