Base | Representation |
---|---|
bin | 111101011110010001… |
… | …0010001111110010100 |
3 | 110121202011002122010000 |
4 | 1322330202101332110 |
5 | 4130330100401004 |
6 | 140351233531300 |
7 | 12352245344160 |
oct | 1727442217624 |
9 | 417664078100 |
10 | 132012122004 |
11 | 50a93446184 |
12 | 21702713b30 |
13 | c5aaa04579 |
14 | 65647dbca0 |
15 | 367981cc39 |
hex | 1ebc891f94 |
132012122004 has 120 divisors (see below), whose sum is σ = 397054627200. Its totient is φ = 37464513984.
The previous prime is 132012122003. The next prime is 132012122041. The reversal of 132012122004 is 400221210231.
It is a happy number.
132012122004 is a `hidden beast` number, since 1 + 320 + 121 + 220 + 0 + 4 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132012122003) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 142609 + ... + 533255.
It is an arithmetic number, because the mean of its divisors is an integer number (3308788560).
Almost surely, 2132012122004 is an apocalyptic number.
132012122004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132012122004, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198527313600).
132012122004 is an abundant number, since it is smaller than the sum of its proper divisors (265042505196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132012122004 is a wasteful number, since it uses less digits than its factorization.
132012122004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390819 (or 390808 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 132012122004 its reverse (400221210231), we get a palindrome (532233332235).
It can be divided in two parts, 132012 and 122004, that added together give a square (254016 = 5042).
The spelling of 132012122004 in words is "one hundred thirty-two billion, twelve million, one hundred twenty-two thousand, four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •