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1320131210112 = 2732111322073631
BaseRepresentation
bin10011001101011101111…
…100111010101110000000
311200012111012202212220200
4103031131330322232000
5133112112042210422
62450243201205200
7164243040066141
oct23153574725600
94605435685820
101320131210112
1146995671a320
12193a25330800
1397645a225a0
1447c75067ac8
152451645d2ac
hex1335df3ab80

1320131210112 has 384 divisors, whose sum is σ = 4466195435520. Its totient is φ = 368998502400.

The previous prime is 1320131210093. The next prime is 1320131210119. The reversal of 1320131210112 is 2110121310231.

1320131210112 is a `hidden beast` number, since 1 + 320 + 131 + 210 + 1 + 1 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320131210119) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 363570537 + ... + 363574167.

It is an arithmetic number, because the mean of its divisors is an integer number (11630717280).

Almost surely, 21320131210112 is an apocalyptic number.

1320131210112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1320131210112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2233097717760).

1320131210112 is an abundant number, since it is smaller than the sum of its proper divisors (3146064225408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320131210112 is a wasteful number, since it uses less digits than its factorization.

1320131210112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5882 (or 5867 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1320131210112 its reverse (2110121310231), we get a palindrome (3430252520343).

The spelling of 1320131210112 in words is "one trillion, three hundred twenty billion, one hundred thirty-one million, two hundred ten thousand, one hundred twelve".