Base | Representation |
---|---|
bin | 11110000001000011001100… |
… | …001111100011111001001100 |
3 | 122022102101000200110121202110 |
4 | 132001003030033203321030 |
5 | 114300402213102103400 |
6 | 1144434103403024020 |
7 | 36543443423440614 |
oct | 3601031417437114 |
9 | 568371020417673 |
10 | 132013541441100 |
11 | 390776a0615150 |
12 | 12981137b0b010 |
13 | 5887a92422aa7 |
14 | 24856bd279a44 |
15 | 103de962c9e50 |
hex | 7810cc3e3e4c |
132013541441100 has 144 divisors (see below), whose sum is σ = 422551513472256. Its totient is φ = 31552532256000.
The previous prime is 132013541441099. The next prime is 132013541441123. The reversal of 132013541441100 is 1144145310231.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 281484739 + ... + 281953338.
It is an arithmetic number, because the mean of its divisors is an integer number (2934385510224).
Almost surely, 2132013541441100 is an apocalyptic number.
132013541441100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132013541441100 is an abundant number, since it is smaller than the sum of its proper divisors (290537972031156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132013541441100 is a wasteful number, since it uses less digits than its factorization.
132013541441100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 563438176 (or 563438169 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 132013541441100 its reverse (1144145310231), we get a palindrome (133157686751331).
The spelling of 132013541441100 in words is "one hundred thirty-two trillion, thirteen billion, five hundred forty-one million, four hundred forty-one thousand, one hundred".
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