Base | Representation |
---|---|
bin | 11110000001000100000111… |
… | …011111101101101010000010 |
3 | 122022102110120222000121221000 |
4 | 132001010013133231222002 |
5 | 114300411232043444023 |
6 | 1144434350153512430 |
7 | 36543510154165401 |
oct | 3601040737555202 |
9 | 568373528017830 |
10 | 132014535531138 |
11 | 39078060771767 |
12 | 12981374a12716 |
13 | 5887bc0370c50 |
14 | 24857752c9638 |
15 | 103e0036e0243 |
hex | 7811077eda82 |
132014535531138 has 64 divisors (see below), whose sum is σ = 315942407665920. Its totient is φ = 40618547473536.
The previous prime is 132014535531121. The next prime is 132014535531227. The reversal of 132014535531138 is 831135535410231.
132014535531138 is a `hidden beast` number, since 1 + 3 + 2 + 0 + 1 + 4 + 53 + 553 + 11 + 38 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 132014535531093 and 132014535531102.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18870331 + ... + 24902177.
It is an arithmetic number, because the mean of its divisors is an integer number (4936600119780).
Almost surely, 2132014535531138 is an apocalyptic number.
132014535531138 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
132014535531138 is an abundant number, since it is smaller than the sum of its proper divisors (183927872134782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132014535531138 is a wasteful number, since it uses less digits than its factorization.
132014535531138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6063048 (or 6063042 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 45.
The spelling of 132014535531138 in words is "one hundred thirty-two trillion, fourteen billion, five hundred thirty-five million, five hundred thirty-one thousand, one hundred thirty-eight".
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