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13202201100000 = 25355112367991
BaseRepresentation
bin1100000000011110000010…
…0000011011111011100000
31201202010012002112200100010
43000013200200123323200
53212301101440200000
644025001335524520
72531553564525513
oct300074040337340
951663162480303
1013202201100000
114230027381a00
121592812529740
13749c68002813
14338dc058cd7a
1517d645e93d50
hexc01e081bee0

13202201100000 has 864 divisors, whose sum is σ = 47790757195776. Its totient is φ = 3188592000000.

The previous prime is 13202201099929. The next prime is 13202201100013. The reversal of 13202201100000 is 110220231.

It is a super-2 number, since 2×132022011000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 13322099505 + ... + 13322100495.

It is an arithmetic number, because the mean of its divisors is an integer number (55313376384).

Almost surely, 213202201100000 is an apocalyptic number.

13202201100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13202201100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23895378597888).

13202201100000 is an abundant number, since it is smaller than the sum of its proper divisors (34588556095776).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13202201100000 is an equidigital number, since it uses as much as digits as its factorization.

13202201100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1418 (or 1379 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 13202201100000 its reverse (110220231), we get a palindrome (13202311320231).

The spelling of 13202201100000 in words is "thirteen trillion, two hundred two billion, two hundred one million, one hundred thousand".