Base | Representation |
---|---|
bin | 111101100000111101… |
… | …0010101000010101111 |
3 | 110121222102210202200100 |
4 | 1323001322111002233 |
5 | 4131021142441421 |
6 | 140404215002143 |
7 | 12354422061120 |
oct | 1730172250257 |
9 | 417872722610 |
10 | 132102312111 |
11 | 5102a347360 |
12 | 21728969353 |
13 | c5c35c1bb3 |
14 | 6572798047 |
15 | 36826d5c26 |
hex | 1ec1e950af |
132102312111 has 48 divisors (see below), whose sum is σ = 250419536640. Its totient is φ = 65012751360.
The previous prime is 132102312109. The next prime is 132102312119. The reversal of 132102312111 is 111213201231.
132102312111 is a `hidden beast` number, since 1 + 321 + 0 + 231 + 2 + 111 = 666.
It is not a de Polignac number, because 132102312111 - 21 = 132102312109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132102312119) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5003250 + ... + 5029583.
It is an arithmetic number, because the mean of its divisors is an integer number (5217073680).
Almost surely, 2132102312111 is an apocalyptic number.
132102312111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132102312111 is a deficient number, since it is larger than the sum of its proper divisors (118317224529).
132102312111 is a wasteful number, since it uses less digits than its factorization.
132102312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10032876 (or 10032873 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 132102312111 its reverse (111213201231), we get a palindrome (243315513342).
The spelling of 132102312111 in words is "one hundred thirty-two billion, one hundred two million, three hundred twelve thousand, one hundred eleven".
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