Base | Representation |
---|---|
bin | 111101100001000001… |
… | …0010101001110001111 |
3 | 110121222120202100102220 |
4 | 1323002002111032033 |
5 | 4131022212104444 |
6 | 140404331550423 |
7 | 12354445646322 |
oct | 1730202251617 |
9 | 417876670386 |
10 | 132104409999 |
11 | 5103054a551 |
12 | 217295bb413 |
13 | c5c3b77a53 |
14 | 6572b827b9 |
15 | 368299c619 |
hex | 1ec209538f |
132104409999 has 8 divisors (see below), whose sum is σ = 186500343600. Its totient is φ = 82889041536.
The previous prime is 132104409947. The next prime is 132104410001. The reversal of 132104409999 is 999904401231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132104409999 - 223 = 132096021391 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51), and also a Moran number because the ratio is a prime number: 2590282549 = 132104409999 / (1 + 3 + 2 + 1 + 0 + 4 + 4 + 0 + 9 + 9 + 9 + 9).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132104409919) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1295141224 + ... + 1295141325.
It is an arithmetic number, because the mean of its divisors is an integer number (23312542950).
Almost surely, 2132104409999 is an apocalyptic number.
132104409999 is a deficient number, since it is larger than the sum of its proper divisors (54395933601).
132104409999 is a wasteful number, since it uses less digits than its factorization.
132104409999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2590282569.
The product of its (nonzero) digits is 629856, while the sum is 51.
The spelling of 132104409999 in words is "one hundred thirty-two billion, one hundred four million, four hundred nine thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •