132104410000 has 100 divisors (see below), whose sum is σ = 333744567552. Its totient is φ = 50544208000.

The previous prime is 132104409947. The next prime is 132104410001. The reversal of 132104410000 is 14401231.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (132104410001) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 57184 + ... + 517183.

Almost surely, 2^132104410000 is an apocalyptic number.

132104410000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132104410000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166872283776).

132104410000 is an abundant number, since it is smaller than the sum of its proper divisors (201640157552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132104410000 is an equidigital number, since it uses as much as digits as its factorization.

132104410000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 574418 (or 574397 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 132104410000 its reverse (14401231), we get a palindrome (132118811231).

The spelling of 132104410000 in words is "one hundred thirty-two billion, one hundred four million, four hundred ten thousand".