13211130000 has 100 divisors (see below), whose sum is σ = 42647385968. Its totient is φ = 3522960000.

The previous prime is 13211129993. The next prime is 13211130001. The reversal of 13211130000 is 3111231.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (13211130001) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 190186 + ... + 250185.

Almost surely, 2^13211130000 is an apocalyptic number.

13211130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13211130000 is an abundant number, since it is smaller than the sum of its proper divisors (29436255968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13211130000 is an equidigital number, since it uses as much as digits as its factorization.

13211130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440402 (or 440381 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 13211130000 its reverse (3111231), we get a palindrome (13214241231).

The spelling of 13211130000 in words is "thirteen billion, two hundred eleven million, one hundred thirty thousand".