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1321212111223 is a prime number
BaseRepresentation
bin10011001110011110011…
…000001110100101110111
311200022021112200100111011
4103032132120032211313
5133121320300024343
62450542332453051
7164311603435264
oct23163630164567
94608245610434
101321212111223
1146a36087a324
1219408731a187
1397788947044
1447d3883426b
152457b2c029d
hex1339e60e977

1321212111223 has 2 divisors, whose sum is σ = 1321212111224. Its totient is φ = 1321212111222.

The previous prime is 1321212111217. The next prime is 1321212111259. The reversal of 1321212111223 is 3221112121231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1321212111223 - 213 = 1321212103031 is a prime.

It is a super-4 number, since 4×13212121112234 (a number of 50 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1321212111194 and 1321212111203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321212111283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660606055611 + 660606055612.

It is an arithmetic number, because the mean of its divisors is an integer number (660606055612).

Almost surely, 21321212111223 is an apocalyptic number.

1321212111223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321212111223 is an equidigital number, since it uses as much as digits as its factorization.

1321212111223 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288, while the sum is 22.

Adding to 1321212111223 its reverse (3221112121231), we get a palindrome (4542324232454).

The spelling of 1321212111223 in words is "one trillion, three hundred twenty-one billion, two hundred twelve million, one hundred eleven thousand, two hundred twenty-three".