Search a number
-
+
13212130022100 = 22325214680144469
BaseRepresentation
bin1100000001000011000001…
…0100010001001011010100
31201210001211001120011220200
43000100300110101023110
53212431420241201400
644033322503100500
72532354620134332
oct300206024211324
951701731504820
1013212130022100
114234261a5a049
121594723741730
1374ab8b064959
143396830ccb52
1517da279b1b00
hexc04305112d4

13212130022100 has 54 divisors (see below), whose sum is σ = 41412687549870. Its totient is φ = 3523234672320.

The previous prime is 13212130022081. The next prime is 13212130022107. The reversal of 13212130022100 is 122003121231.

13212130022100 is a `hidden beast` number, since 1 + 32 + 121 + 300 + 2 + 210 + 0 = 666.

It can be written as a sum of positive squares in 3 ways, for example, as 16841291076 + 13195288731024 = 129774^2 + 3632532^2 .

It is a super-2 number, since 2×132121300221002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13212130022107) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 7340071335 + ... + 7340073134.

Almost surely, 213212130022100 is an apocalyptic number.

13212130022100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13212130022100 is an abundant number, since it is smaller than the sum of its proper divisors (28200557527770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13212130022100 is a wasteful number, since it uses less digits than its factorization.

13212130022100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14680144489 (or 14680144479 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13212130022100 its reverse (122003121231), we get a palindrome (13334133143331).

The spelling of 13212130022100 in words is "thirteen trillion, two hundred twelve billion, one hundred thirty million, twenty-two thousand, one hundred".

Divisors: 1 2 3 4 5 6 9 10 12 15 18 20 25 30 36 45 50 60 75 90 100 150 180 225 300 450 900 14680144469 29360288938 44040433407 58720577876 73400722345 88080866814 132121300221 146801444690 176161733628 220202167035 264242600442 293602889380 367003611725 440404334070 528485200884 660606501105 734007223450 880808668140 1101010835175 1321213002210 1468014446900 2202021670350 2642426004420 3303032505525 4404043340700 6606065011050 13212130022100