Base | Representation |
---|---|
bin | 11110000100011010010111… |
… | …001111000010011101100100 |
3 | 122100020110101011221000211010 |
4 | 132010122113033002131210 |
5 | 114313143400032030300 |
6 | 1145132153240342220 |
7 | 36566232660641064 |
oct | 3604322717023544 |
9 | 570213334830733 |
10 | 132244580345700 |
11 | 3915667aaa5819 |
12 | 129b9a76474970 |
13 | 58a37c21162b4 |
14 | 249295975d3a4 |
15 | 1044eb9691a50 |
hex | 7846973c2764 |
132244580345700 has 72 divisors (see below), whose sum is σ = 394970479993600. Its totient is φ = 34127633635200.
The previous prime is 132244580345659. The next prime is 132244580345729. The reversal of 132244580345700 is 7543085442231.
It is a self number, because there is not a number n which added to its sum of digits gives 132244580345700.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7109914375 + ... + 7109932974.
Almost surely, 2132244580345700 is an apocalyptic number.
132244580345700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132244580345700 is an abundant number, since it is smaller than the sum of its proper divisors (262725899647900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132244580345700 is a wasteful number, since it uses less digits than its factorization.
132244580345700 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14219847397 (or 14219847390 counting only the distinct ones).
The product of its (nonzero) digits is 3225600, while the sum is 48.
The spelling of 132244580345700 in words is "one hundred thirty-two trillion, two hundred forty-four billion, five hundred eighty million, three hundred forty-five thousand, seven hundred".
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