Base | Representation |
---|---|
bin | 11000101001010000… |
… | …11011010110100111 |
3 | 1021011002112200020221 |
4 | 30110220123112213 |
5 | 204044121402012 |
6 | 10024523105211 |
7 | 645610006216 |
oct | 142450332647 |
9 | 37132480227 |
10 | 13231044007 |
11 | 567a641215 |
12 | 2693072207 |
13 | 132b20822c |
14 | 8d730d07d |
15 | 52688e507 |
hex | 314a1b5a7 |
13231044007 has 2 divisors, whose sum is σ = 13231044008. Its totient is φ = 13231044006.
The previous prime is 13231043977. The next prime is 13231044037. The reversal of 13231044007 is 70044013231.
13231044007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (13231043977) and next prime (13231044037).
It is a cyclic number.
It is not a de Polignac number, because 13231044007 - 215 = 13231011239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231044037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615522003 + 6615522004.
It is an arithmetic number, because the mean of its divisors is an integer number (6615522004).
Almost surely, 213231044007 is an apocalyptic number.
13231044007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231044007 is an equidigital number, since it uses as much as digits as its factorization.
13231044007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 13231044007 its reverse (70044013231), we get a palindrome (83275057238).
The spelling of 13231044007 in words is "thirteen billion, two hundred thirty-one million, forty-four thousand, seven".
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