13231130000 has 100 divisors (see below), whose sum is σ = 34946351088. Its totient is φ = 4811280000.

The previous prime is 13231129973. The next prime is 13231130009. The reversal of 13231130000 is 3113231.

It is a tau number, because it is divible by the number of its divisors (100).

It is not an unprimeable number, because it can be changed into a prime (13231130009) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 49859 + ... + 170141.

Almost surely, 2^13231130000 is an apocalyptic number.

13231130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13231130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17473175544).

13231130000 is an abundant number, since it is smaller than the sum of its proper divisors (21715221088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13231130000 is a wasteful number, since it uses less digits than its factorization.

13231130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120322 (or 120301 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13231130000 its reverse (3113231), we get a palindrome (13234243231).

The spelling of 13231130000 in words is "thirteen billion, two hundred thirty-one million, one hundred thirty thousand".