1323144025140 has 192 divisors, whose sum is σ = 4310826283008. Its totient is φ = 296983680000.

The previous prime is 1323144025129. The next prime is 1323144025153. The reversal of 1323144025140 is 415204413231.

It is a super-2 number, since 2×1323144025140² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1323144025098 and 1323144025107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7396432 + ... + 7573208.

It is an arithmetic number, because the mean of its divisors is an integer number (22452220224).

Almost surely, 2^{1323144025140} is an apocalyptic number.

1323144025140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1323144025140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2155413141504).

1323144025140 is an abundant number, since it is smaller than the sum of its proper divisors (2987682257868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1323144025140 is a wasteful number, since it uses less digits than its factorization.

1323144025140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177118 (or 177116 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 1323144025140 its reverse (415204413231), we get a palindrome (1738348438371).

The spelling of 1323144025140 in words is "one trillion, three hundred twenty-three billion, one hundred forty-four million, twenty-five thousand, one hundred forty".