Base | Representation |
---|---|
bin | 111101100111011100… |
… | …0110100100011111110 |
3 | 110122112121110111202200 |
4 | 1323032320310203332 |
5 | 4131442411130414 |
6 | 140441553132330 |
7 | 12363004422126 |
oct | 1731670644376 |
9 | 418477414680 |
10 | 132320020734 |
11 | 51131225040 |
12 | 2178985a0a6 |
13 | c629739675 |
14 | 6593669c86 |
15 | 369688c109 |
hex | 1ecee348fe |
132320020734 has 48 divisors (see below), whose sum is σ = 316270571760. Its totient is φ = 39646442880.
The previous prime is 132320020681. The next prime is 132320020771. The reversal of 132320020734 is 437020023231.
132320020734 is a `hidden beast` number, since 132 + 320 + 0 + 207 + 3 + 4 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 132320020698 and 132320020707.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3736777 + ... + 3772020.
It is an arithmetic number, because the mean of its divisors is an integer number (6588970245).
Almost surely, 2132320020734 is an apocalyptic number.
132320020734 is an abundant number, since it is smaller than the sum of its proper divisors (183950551026).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132320020734 is a wasteful number, since it uses less digits than its factorization.
132320020734 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7508905 (or 7508902 counting only the distinct ones).
The product of its (nonzero) digits is 6048, while the sum is 27.
Adding to 132320020734 its reverse (437020023231), we get a palindrome (569340043965).
The spelling of 132320020734 in words is "one hundred thirty-two billion, three hundred twenty million, twenty thousand, seven hundred thirty-four".
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