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132324424000 = 265324168633
BaseRepresentation
bin111101100111100100…
…1100111100101000000
3110122112220202012220121
41323033021213211000
54132000023032000
6140442231350024
712363060021466
oct1731711474500
9418486665817
10132324424000
11511337622aa
122178b222314
13c62a61b952
146594094836
153696e5bb1a
hex1ecf267940

132324424000 has 112 divisors (see below), whose sum is σ = 329065987536. Its totient is φ = 52709376000.

The previous prime is 132324423997. The next prime is 132324424007. The reversal of 132324424000 is 424423231.

It is a happy number.

It can be written as a sum of positive squares in 8 ways, for example, as 14993512704 + 117330911296 = 122448^2 + 342536^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132324424007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1893684 + ... + 1962316.

Almost surely, 2132324424000 is an apocalyptic number.

132324424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132324424000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164532993768).

132324424000 is an abundant number, since it is smaller than the sum of its proper divisors (196741563536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132324424000 is an equidigital number, since it uses as much as digits as its factorization.

132324424000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68901 (or 68881 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 132324424000 its reverse (424423231), we get a palindrome (132748847231).

The spelling of 132324424000 in words is "one hundred thirty-two billion, three hundred twenty-four million, four hundred twenty-four thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 64 80 100 125 160 200 241 250 320 400 482 500 800 964 1000 1205 1600 1928 2000 2410 3856 4000 4820 6025 7712 8000 9640 12050 15424 19280 24100 30125 38560 48200 60250 68633 77120 96400 120500 137266 192800 241000 274532 343165 385600 482000 549064 686330 964000 1098128 1372660 1715825 1928000 2196256 2745320 3431650 4392512 5490640 6863300 8579125 10981280 13726600 16540553 17158250 21962560 27453200 33081106 34316500 54906400 66162212 68633000 82702765 109812800 132324424 137266000 165405530 264648848 274532000 330811060 413513825 529297696 549064000 661622120 827027650 1058595392 1323244240 1654055300 2067569125 2646488480 3308110600 4135138250 5292976960 6616221200 8270276500 13232442400 16540553000 26464884800 33081106000 66162212000 132324424000