Base | Representation |
---|---|
bin | 11110000101101011111110… |
… | …000010010010000110010000 |
3 | 122100112211112212001020121002 |
4 | 132011223332002102012100 |
5 | 114321112323311313130 |
6 | 1145240324144121132 |
7 | 36605454250060220 |
oct | 3605537602220620 |
9 | 570484485036532 |
10 | 132332204401040 |
11 | 3918a855544486 |
12 | 12a12a4b6061a8 |
13 | 58abb47922b57 |
14 | 2496cacca0080 |
15 | 10473e7149b45 |
hex | 785afe092190 |
132332204401040 has 80 divisors (see below), whose sum is σ = 351631740878208. Its totient is φ = 45370245485568.
The previous prime is 132332204400997. The next prime is 132332204401057. The reversal of 132332204401040 is 40104402233231.
It is a tau number, because it is divible by the number of its divisors (80).
It is a junction number, because it is equal to n+sod(n) for n = 132332204400994 and 132332204401012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30325604 + ... + 34413756.
Almost surely, 2132332204401040 is an apocalyptic number.
132332204401040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132332204401040 is an abundant number, since it is smaller than the sum of its proper divisors (219299536477168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132332204401040 is a wasteful number, since it uses less digits than its factorization.
132332204401040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4145976 (or 4145970 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 132332204401040 its reverse (40104402233231), we get a palindrome (172436606634271).
The spelling of 132332204401040 in words is "one hundred thirty-two trillion, three hundred thirty-two billion, two hundred four million, four hundred one thousand, forty".
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