Base | Representation |
---|---|
bin | 11110000111001101011000… |
… | …100110111000101101110110 |
3 | 122100220211112112001210110220 |
4 | 132013031120212320231312 |
5 | 114324321033102122300 |
6 | 1145400343310355210 |
7 | 36616146304625061 |
oct | 3607153046705566 |
9 | 570824475053426 |
10 | 132436803160950 |
11 | 39220150844a02 |
12 | 12a2b1814bbb06 |
13 | 58b89771072b2 |
14 | 249bd929b78d8 |
15 | 1049eb9e7eda0 |
hex | 7873589b8b76 |
132436803160950 has 48 divisors (see below), whose sum is σ = 330110496642960. Its totient is φ = 35137209358720.
The previous prime is 132436803160933. The next prime is 132436803160969. The reversal of 132436803160950 is 59061308634231.
It is a happy number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 132436803160893 and 132436803160902.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2240863905 + ... + 2240923004.
It is an arithmetic number, because the mean of its divisors is an integer number (6877302013395).
Almost surely, 2132436803160950 is an apocalyptic number.
132436803160950 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132436803160950 is an abundant number, since it is smaller than the sum of its proper divisors (197673693482010).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132436803160950 is a wasteful number, since it uses less digits than its factorization.
132436803160950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4481787121 (or 4481787116 counting only the distinct ones).
The product of its (nonzero) digits is 2799360, while the sum is 51.
The spelling of 132436803160950 in words is "one hundred thirty-two trillion, four hundred thirty-six billion, eight hundred three million, one hundred sixty thousand, nine hundred fifty".
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