Base | Representation |
---|---|
bin | 111101101100011001… |
… | …1000000101011110000 |
3 | 110122222012021211110001 |
4 | 1323120303000223300 |
5 | 4132312441112210 |
6 | 140510252315344 |
7 | 12400063466002 |
oct | 1733063005360 |
9 | 418865254401 |
10 | 132486269680 |
11 | 51207055366 |
12 | 21815472b54 |
13 | c65500751b |
14 | 65ab784372 |
15 | 36a627b03a |
hex | 1ed8cc0af0 |
132486269680 has 40 divisors (see below), whose sum is σ = 308311574832. Its totient is φ = 52946164224.
The previous prime is 132486269579. The next prime is 132486269683. The reversal of 132486269680 is 86962684231.
It is a tau number, because it is divible by the number of its divisors (40).
It is a super-3 number, since 3×1324862696803 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132486269683) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 667062 + ... + 842581.
Almost surely, 2132486269680 is an apocalyptic number.
132486269680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132486269680 is an abundant number, since it is smaller than the sum of its proper divisors (175825305152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132486269680 is a wasteful number, since it uses less digits than its factorization.
132486269680 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1510753 (or 1510747 counting only the distinct ones).
The product of its (nonzero) digits is 5971968, while the sum is 55.
The spelling of 132486269680 in words is "one hundred thirty-two billion, four hundred eighty-six million, two hundred sixty-nine thousand, six hundred eighty".
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