Base | Representation |
---|---|
bin | 1100000110001010011110… |
… | …1000011100000111010000 |
3 | 1202002110201001000212002220 |
4 | 3001202213220130013100 |
5 | 3220401430433110100 |
6 | 44141541105141040 |
7 | 2541616112300040 |
oct | 301424750340720 |
9 | 52073631025086 |
10 | 13300031144400 |
11 | 4268569939270 |
12 | 15a977562a780 |
13 | 75625909cb60 |
14 | 33da21353720 |
15 | 180e6e948aa0 |
hex | c18a7a1c1d0 |
13300031144400 has 3840 divisors, whose sum is σ = 64456034549760. Its totient is φ = 2251830067200.
The previous prime is 13300031144399. The next prime is 13300031144447. The reversal of 13300031144400 is 444113000331.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 767 ways as a sum of consecutive naturals, for example, 21911088897 + ... + 21911089503.
It is an arithmetic number, because the mean of its divisors is an integer number (16785425664).
Almost surely, 213300031144400 is an apocalyptic number.
13300031144400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13300031144400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32228017274880).
13300031144400 is an abundant number, since it is smaller than the sum of its proper divisors (51156003405360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300031144400 is a wasteful number, since it uses less digits than its factorization.
13300031144400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 742 (or 731 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13300031144400 its reverse (444113000331), we get a palindrome (13744144144731).
It can be divided in two parts, 13300031 and 144400, that added together give a palindrome (13444431).
The spelling of 13300031144400 in words is "thirteen trillion, three hundred billion, thirty-one million, one hundred forty-four thousand, four hundred".
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