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13301014271 is a prime number
BaseRepresentation
bin11000110001100110…
…10101111011111111
31021022222012112102012
430120303111323333
5204220024424041
610035502521435
7650416520156
oct143063257377
937288175365
1013301014271
115706091986
1226b259627b
13133c86635c
1490272459d
1552cab13eb
hex318cd5eff

13301014271 has 2 divisors, whose sum is σ = 13301014272. Its totient is φ = 13301014270.

The previous prime is 13301014211. The next prime is 13301014273. The reversal of 13301014271 is 17241010331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13301014271 - 210 = 13301013247 is a prime.

It is a super-2 number, since 2×133010142712 (a number of 21 digits) contains 22 as substring.

Together with 13301014273, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13301014273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650507135 + 6650507136.

It is an arithmetic number, because the mean of its divisors is an integer number (6650507136).

Almost surely, 213301014271 is an apocalyptic number.

13301014271 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301014271 is an equidigital number, since it uses as much as digits as its factorization.

13301014271 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

The spelling of 13301014271 in words is "thirteen billion, three hundred one million, fourteen thousand, two hundred seventy-one".