Base | Representation |
---|---|
bin | 1100000110001111010110… |
… | …1101101011100010000000 |
3 | 1202002121002100000120202221 |
4 | 3001203311231223202000 |
5 | 3220412121313003440 |
6 | 44142315103020424 |
7 | 2541663430134334 |
oct | 301436555534200 |
9 | 52077070016687 |
10 | 13301341141120 |
11 | 426908134418a |
12 | 15a9a8029a714 |
13 | 7564075c8046 |
14 | 33db073177c4 |
15 | 180ee9960d4a |
hex | c18f5b6b880 |
13301341141120 has 32 divisors (see below), whose sum is σ = 31798518667020. Its totient is φ = 5320536456192.
The previous prime is 13301341141051. The next prime is 13301341141133. The reversal of 13301341141120 is 2114114310331.
It can be written as a sum of positive squares in 2 ways, for example, as 13300725704256 + 615436864 = 3647016^2 + 24808^2 .
It is a tau number, because it is divible by the number of its divisors (32).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10391672127 + ... + 10391673406.
Almost surely, 213301341141120 is an apocalyptic number.
13301341141120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13301341141120 is an abundant number, since it is smaller than the sum of its proper divisors (18497177525900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13301341141120 is an equidigital number, since it uses as much as digits as its factorization.
13301341141120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20783345552 (or 20783345540 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 13301341141120 its reverse (2114114310331), we get a palindrome (15415455451451).
The spelling of 13301341141120 in words is "thirteen trillion, three hundred one billion, three hundred forty-one million, one hundred forty-one thousand, one hundred twenty".
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