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133025510401212 = 22311134139746110331
BaseRepresentation
bin11110001111110001101010…
…010010110010010010111100
3122110000010002112121012212110
4132033301222102302102330
5114413442221130314322
61150531024213534020
740006530104614242
oct3617615222622274
9573003075535773
10133025510401212
1139427890720a10
1212b0529a344310
13592c3372a5a40
1424bc67d140792
15105a4736cec0c
hex78fc6a4b24bc

133025510401212 has 384 divisors, whose sum is σ = 375341036184576. Its totient is φ = 36128885760000.

The previous prime is 133025510401207. The next prime is 133025510401219. The reversal of 133025510401212 is 212104015520331.

It is a happy number.

It is a super-2 number, since 2×1330255104012122 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 133025510401212.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133025510401219) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 12876338887 + ... + 12876349217.

It is an arithmetic number, because the mean of its divisors is an integer number (977450615064).

Almost surely, 2133025510401212 is an apocalyptic number.

133025510401212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133025510401212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187670518092288).

133025510401212 is an abundant number, since it is smaller than the sum of its proper divisors (242315525783364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133025510401212 is a wasteful number, since it uses less digits than its factorization.

133025510401212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11261 (or 11259 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 133025510401212 its reverse (212104015520331), we get a palindrome (345129525921543).

The spelling of 133025510401212 in words is "one hundred thirty-three trillion, twenty-five billion, five hundred ten million, four hundred one thousand, two hundred twelve".