Base | Representation |
---|---|
bin | 11110001111110001101010… |
… | …100110011111000001000100 |
3 | 122110000010002220022120102110 |
4 | 132033301222212133001010 |
5 | 114413442223441040444 |
6 | 1150531024520341020 |
7 | 40006530166532340 |
oct | 3617615246370104 |
9 | 573003086276373 |
10 | 133025515565124 |
11 | 39427893628706 |
12 | 12b052a0014770 |
13 | 592c338393300 |
14 | 24bc67dac6620 |
15 | 105a473d9ecb9 |
hex | 78fc6a99f044 |
133025515565124 has 72 divisors (see below), whose sum is σ = 384121015400640. Its totient is φ = 35083652452992.
The previous prime is 133025515565123. The next prime is 133025515565153. The reversal of 133025515565124 is 421565515520331.
133025515565124 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (133025515565123) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4685302639 + ... + 4685331030.
Almost surely, 2133025515565124 is an apocalyptic number.
133025515565124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
133025515565124 is an abundant number, since it is smaller than the sum of its proper divisors (251095499835516).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133025515565124 is a wasteful number, since it uses less digits than its factorization.
133025515565124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9370633709 (or 9370633694 counting only the distinct ones).
The product of its (nonzero) digits is 2700000, while the sum is 48.
The spelling of 133025515565124 in words is "one hundred thirty-three trillion, twenty-five billion, five hundred fifteen million, five hundred sixty-five thousand, one hundred twenty-four".
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