Base | Representation |
---|---|
bin | 11110010000110111001000… |
… | …001011100110011100100100 |
3 | 122110021020121211010110010020 |
4 | 132100313020023212130210 |
5 | 114421203001101120004 |
6 | 1151025201500155140 |
7 | 40015110362121555 |
oct | 3620671013463444 |
9 | 573236554113106 |
10 | 133100100020004 |
11 | 39456487604567 |
12 | 12b17836238ab0 |
13 | 5936393544450 |
14 | 24c211751032c |
15 | 105c38bbd28d9 |
hex | 790dc82e6724 |
133100100020004 has 48 divisors (see below), whose sum is σ = 334469818959360. Its totient is φ = 40952265822720.
The previous prime is 133100100019987. The next prime is 133100100020021. The reversal of 133100100020004 is 400020001001331.
It is an interprime number because it is at equal distance from previous prime (133100100019987) and next prime (133100100020021).
It is a super-3 number, since 3×1331001000200043 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12801157 + ... + 20738124.
It is an arithmetic number, because the mean of its divisors is an integer number (6968121228320).
Almost surely, 2133100100020004 is an apocalyptic number.
It is an amenable number.
133100100020004 is an abundant number, since it is smaller than the sum of its proper divisors (201369718939356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133100100020004 is a wasteful number, since it uses less digits than its factorization.
133100100020004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33564740 (or 33564738 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 133100100020004 its reverse (400020001001331), we get a palindrome (533120101021335).
The spelling of 133100100020004 in words is "one hundred thirty-three trillion, one hundred billion, one hundred million, twenty thousand, four".
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