133104041141 has 4 divisors (see below), whose sum is σ = 133150730784. Its totient is φ = 133057351500.

The previous prime is 133104041111. The next prime is 133104041171. The reversal of 133104041141 is 141140401331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (133104041111) and next prime (133104041171).

It is a cyclic number.

It is not a de Polignac number, because 133104041141 - 2²² = 133099846837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133104041111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23340545 + ... + 23346246.

It is an arithmetic number, because the mean of its divisors is an integer number (33287682696).

Almost surely, 2^133104041141 is an apocalyptic number.

It is an amenable number.

133104041141 is a deficient number, since it is larger than the sum of its proper divisors (46689643).

133104041141 is an equidigital number, since it uses as much as digits as its factorization.

133104041141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46689642.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 133104041141 its reverse (141140401331), we get a palindrome (274244442472).

The spelling of 133104041141 in words is "one hundred thirty-three billion, one hundred four million, forty-one thousand, one hundred forty-one".