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133104041142 = 2322184006857
BaseRepresentation
bin111101111110110011…
…1100111110010110110
3110201120020201212120120
41323331213213302312
54140044113304032
6141051441312410
712421304452662
oct1737547476266
9421506655516
10133104041142
11514a3841196
1221968335706
13c722cb6077
1466298358a2
1536e060962c
hex1efd9e7cb6

133104041142 has 8 divisors (see below), whose sum is σ = 266208082296. Its totient is φ = 44368013712.

The previous prime is 133104041111. The next prime is 133104041171. The reversal of 133104041142 is 241140401331.

133104041142 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

133104041142 is an admirable number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11092003423 + ... + 11092003434.

It is an arithmetic number, because the mean of its divisors is an integer number (33276010287).

Almost surely, 2133104041142 is an apocalyptic number.

133104041142 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133104041142 is a wasteful number, since it uses less digits than its factorization.

133104041142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22184006862.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 133104041142 its reverse (241140401331), we get a palindrome (374244442473).

The spelling of 133104041142 in words is "one hundred thirty-three billion, one hundred four million, forty-one thousand, one hundred forty-two".

Divisors: 1 2 3 6 22184006857 44368013714 66552020571 133104041142