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133104041143 = 1741271897177
BaseRepresentation
bin111101111110110011…
…1100111110010110111
3110201120020201212120121
41323331213213302313
54140044113304033
6141051441312411
712421304452663
oct1737547476267
9421506655517
10133104041143
11514a3841197
1221968335707
13c722cb6078
1466298358a3
1536e060962d
hex1efd9e7cb7

133104041143 has 8 divisors (see below), whose sum is σ = 140967914112. Its totient is φ = 125243970816.

The previous prime is 133104041111. The next prime is 133104041171. The reversal of 133104041143 is 341140401331.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133104041143 - 25 = 133104041111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133104041443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 878430 + ... + 1018747.

It is an arithmetic number, because the mean of its divisors is an integer number (17620989264).

Almost surely, 2133104041143 is an apocalyptic number.

133104041143 is a deficient number, since it is larger than the sum of its proper divisors (7863872969).

133104041143 is a wasteful number, since it uses less digits than its factorization.

133104041143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1901321.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 133104041143 its reverse (341140401331), we get a palindrome (474244442474).

The spelling of 133104041143 in words is "one hundred thirty-three billion, one hundred four million, forty-one thousand, one hundred forty-three".

Divisors: 1 17 4127 70159 1897177 32252009 7829649479 133104041143