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133104055015 = 5171565930059
BaseRepresentation
bin111101111110110011…
…1101011001011100111
3110201120020202120121101
41323331213223023213
54140044114230030
6141051441500531
712421304541301
oct1737547531347
9421506676541
10133104055015
11514a3850658
1221968341747
13c722cbc489
14662983a971
1536e060d7ca
hex1efd9eb2e7

133104055015 has 8 divisors (see below), whose sum is σ = 169120446480. Its totient is φ = 100219523712.

The previous prime is 133104055003. The next prime is 133104055033. The reversal of 133104055015 is 510550401331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133104055015 - 217 = 133103923943 is a prime.

It is a super-2 number, since 2×1331040550152 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 782964945 + ... + 782965114.

It is an arithmetic number, because the mean of its divisors is an integer number (21140055810).

Almost surely, 2133104055015 is an apocalyptic number.

133104055015 is a deficient number, since it is larger than the sum of its proper divisors (36016391465).

133104055015 is a wasteful number, since it uses less digits than its factorization.

133104055015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1565930081.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 133104055015 its reverse (510550401331), we get a palindrome (643654456346).

The spelling of 133104055015 in words is "one hundred thirty-three billion, one hundred four million, fifty-five thousand, fifteen".

Divisors: 1 5 17 85 1565930059 7829650295 26620811003 133104055015