Base | Representation |
---|---|
bin | 111101111110111111… |
… | …0110010001101001100 |
3 | 110201120200011100201220 |
4 | 1323331332302031030 |
5 | 4140102142104400 |
6 | 141052215403340 |
7 | 12421410202326 |
oct | 1737576621514 |
9 | 421520140656 |
10 | 133110113100 |
11 | 514a7209138 |
12 | 2196a383550 |
13 | c724330a43 |
14 | 662a576616 |
15 | 36e0e087a0 |
hex | 1efdfb234c |
133110113100 has 72 divisors (see below), whose sum is σ = 398412364560. Its totient is φ = 34272026880.
The previous prime is 133110113099. The next prime is 133110113119. The reversal of 133110113100 is 1311011331.
It is a super-2 number, since 2×1331101131002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 133110113100.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7641307 + ... + 7658706.
Almost surely, 2133110113100 is an apocalyptic number.
133110113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133110113100 is an abundant number, since it is smaller than the sum of its proper divisors (265302251460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133110113100 is a wasteful number, since it uses less digits than its factorization.
133110113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15300059 (or 15300052 counting only the distinct ones).
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 133110113100 its reverse (1311011331), we get a palindrome (134421124431).
The spelling of 133110113100 in words is "one hundred thirty-three billion, one hundred ten million, one hundred thirteen thousand, one hundred".
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