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13311033120 = 25325711120049
BaseRepresentation
bin11000110010110011…
…00011111100100000
31021100200001112200200
430121121203330200
5204230111024440
610040501345200
7650600625510
oct143131437440
937320045620
1013311033120
115710805220
1226b5a08200
131341963678
14903bb1840
1552d8dec30
hex319663f20

13311033120 has 288 divisors, whose sum is σ = 56632867200. Its totient is φ = 2765905920.

The previous prime is 13311033101. The next prime is 13311033121. The reversal of 13311033120 is 2133011331.

It is a happy number.

13311033120 is a `hidden beast` number, since 1 + 3 + 311 + 0 + 331 + 20 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13311033093 and 13311033102.

It is not an unprimeable number, because it can be changed into a prime (13311033121) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 50856 + ... + 170904.

It is an arithmetic number, because the mean of its divisors is an integer number (196641900).

Almost surely, 213311033120 is an apocalyptic number.

13311033120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311033120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28316433600).

13311033120 is an abundant number, since it is smaller than the sum of its proper divisors (43321834080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311033120 is a wasteful number, since it uses less digits than its factorization.

13311033120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120088 (or 120077 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 13311033120 its reverse (2133011331), we get a palindrome (15444044451).

It can be divided in two parts, 133 and 11033120, that added together give a triangular number (11033253 = T4697).

The spelling of 13311033120 in words is "thirteen billion, three hundred eleven million, thirty-three thousand, one hundred twenty".