1331110001112 has 128 divisors (see below), whose sum is σ = 3441807452160. Its totient is φ = 428678092800.

The previous prime is 1331110001087. The next prime is 1331110001153. The reversal of 1331110001112 is 2111000111331.

It is a junction number, because it is equal to n+sod(n) for n = 1331110001091 and 1331110001100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79399243 + ... + 79416005.

It is an arithmetic number, because the mean of its divisors is an integer number (26889120720).

Almost surely, 2^{1331110001112} is an apocalyptic number.

1331110001112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331110001112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1720903726080).

1331110001112 is an abundant number, since it is smaller than the sum of its proper divisors (2110697451048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331110001112 is a wasteful number, since it uses less digits than its factorization.

1331110001112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17433 (or 17429 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 1331110001112 its reverse (2111000111331), we get a palindrome (3442110112443).

The spelling of 1331110001112 in words is "one trillion, three hundred thirty-one billion, one hundred ten million, one thousand, one hundred twelve".