Base | Representation |
---|---|
bin | 111101111111000001… |
… | …0111100010010111000 |
3 | 110201120202012201210120 |
4 | 1323332002330102320 |
5 | 4140102431444000 |
6 | 141052255013240 |
7 | 12421422362016 |
oct | 1737602742270 |
9 | 421522181716 |
10 | 133111203000 |
11 | 514a7892a86 |
12 | 2196a80a220 |
13 | c724622b59 |
14 | 662a77b8b6 |
15 | 36e10716a0 |
hex | 1efe0bc4b8 |
133111203000 has 128 divisors (see below), whose sum is σ = 415783480320. Its totient is φ = 35455593600.
The previous prime is 133111202993. The next prime is 133111203011. The reversal of 133111203000 is 302111331.
133111203000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2635989 + ... + 2686011.
It is an arithmetic number, because the mean of its divisors is an integer number (3248308440).
Almost surely, 2133111203000 is an apocalyptic number.
133111203000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133111203000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (207891740160).
133111203000 is an abundant number, since it is smaller than the sum of its proper divisors (282672277320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133111203000 is a wasteful number, since it uses less digits than its factorization.
133111203000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50934 (or 50920 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 133111203000 its reverse (302111331), we get a palindrome (133413314331).
The spelling of 133111203000 in words is "one hundred thirty-three billion, one hundred eleven million, two hundred three thousand".
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