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13311141120000 = 211325410631087
BaseRepresentation
bin1100000110110011110111…
…0101101000100000000000
31202010112101022102002111200
43001230331311220200000
53221042204111320000
644151015342341200
72542461325443333
oct301547565504000
952115338362450
1013311141120000
114272250161389
1215ab95628a800
13757309a21709
14340396a9061a
151813beead500
hexc1b3dd68800

13311141120000 has 720 divisors, whose sum is σ = 48130327365120. Its totient is φ = 3543035904000.

The previous prime is 13311141119957. The next prime is 13311141120029. The reversal of 13311141120000 is 2114111331.

It is a happy number.

13311141120000 is a `hidden beast` number, since 13 + 31 + 11 + 411 + 200 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 12245759457 + ... + 12245760543.

It is an arithmetic number, because the mean of its divisors is an integer number (66847676896).

Almost surely, 213311141120000 is an apocalyptic number.

13311141120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311141120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24065163682560).

13311141120000 is an abundant number, since it is smaller than the sum of its proper divisors (34819186245120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311141120000 is a wasteful number, since it uses less digits than its factorization.

13311141120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2198 (or 2160 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13311141120000 its reverse (2114111331), we get a palindrome (13313255231331).

The spelling of 13311141120000 in words is "thirteen trillion, three hundred eleven billion, one hundred forty-one million, one hundred twenty thousand".